(4/3)x-397=603x=

Solution for (4/3)x-397=603x= equation:

(4/3)x-397=603x=

We move all terms to the left:

(4/3)x-397-(603x)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+4/3)x-603x-397=0

We add all the numbers together, and all the variables

-603x+(+4/3)x-397=0

We multiply parentheses

4x^2-603x-397=0

a = 4; b = -603; c = -397;
Δ = b2-4ac
Δ = -6032-4·4·(-397)
Δ = 369961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-603)-\sqrt{369961}}{2*4}=\frac{603-\sqrt{369961}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-603)+\sqrt{369961}}{2*4}=\frac{603+\sqrt{369961}}{8}
$