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(4/3)xx=18
We move all terms to the left:
(4/3)xx-(18)=0
Domain of the equation: 3)xx!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+4/3)xx-18=0
We multiply parentheses
4x^2-18=0
a = 4; b = 0; c = -18;
Δ = b2-4ac
Δ = 02-4·4·(-18)
Δ = 288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{288}=\sqrt{144*2}=\sqrt{144}*\sqrt{2}=12\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{2}}{2*4}=\frac{0-12\sqrt{2}}{8} =-\frac{12\sqrt{2}}{8} =-\frac{3\sqrt{2}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{2}}{2*4}=\frac{0+12\sqrt{2}}{8} =\frac{12\sqrt{2}}{8} =\frac{3\sqrt{2}}{2} $
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