(4/3)y+2=4y-4

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Solution for (4/3)y+2=4y-4 equation: 



(4/3)y+2=4y-4

We move all terms to the left:

(4/3)y+2-(4y-4)=0



Domain of the equation: 3)y!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(+4/3)y-(4y-4)+2=0

We multiply parentheses

4y^2-(4y-4)+2=0

We get rid of parentheses

4y^2-4y+4+2=0

We add all the numbers together, and all the variables

4y^2-4y+6=0

a = 4; b = -4; c = +6;
Δ = b2-4ac
Δ = -42-4·4·6
Δ = -80
Delta is less than zero, so there is no solution for the equation

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