(4/3)y-y-5=-2

Solution for (4/3)y-y-5=-2 equation:

(4/3)y-y-5=-2

We move all terms to the left:

(4/3)y-y-5-(-2)=0


Domain of the equation: 3)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+4/3)y-y-5-(-2)=0

We add all the numbers together, and all the variables

-1y+(+4/3)y-3=0

We multiply parentheses

4y^2-1y-3=0

a = 4; b = -1; c = -3;
Δ = b2-4ac
Δ = -12-4·4·(-3)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-7}{2*4}=\frac{-6}{8}
=-3/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+7}{2*4}=\frac{8}{8}
=1
$