If it's not what You are looking for type in the equation solver your own equation and let us solve it.
35-(4*x) > 2;x
x
(x^2+1)/5
5/(x^2+1)
1/(x^2+1)
1/(x^3+1)
| f(x)=-2.5x^2+5x+10 | | 4a+8=10 | | cos(x)*cosh(x)= | | 3(9a-b)-6(b-9a)= | | 5x-4=0.25x-2 | | y=2x^2-rx+q | | t/6-6=16 | | 5tanx-7sinx=0 | | 6x-2=-2+12x | | 4(2x-1)-2(3x+5)=6 | | 11x+4=8x+37 | | 5=x*0.0045*3600 | | 211=(152)8 | | 10=x*0.0045*3600 | | 20=x*0.0045*3600 | | 8x+1=6x-8 | | 40=x*0.0045*3600 | | 70=x*0.0045*3600 | | cosh(x)*sin(x)= | | cos(x)*sinh(x)= | | 30=x*0.0045*3600 | | sinh(x)*sin(x)= | | 7y-3=4y-9 | | Iog2(1/4) | | -7x-15=2x | | V=(3)(48)(12) | | V=(3.14)(48)(12) | | 5(x-1)=3x-14 | | X=Y*100/Z | | X^6+2x^4-16x^2-32= | | 2*x=3*(cos(x)) | | 2(x)-3cos(x)=0 |