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(4/3y)+(2/5)=3
We move all terms to the left:
(4/3y)+(2/5)-(3)=0
Domain of the equation: 3y)!=0determiningTheFunctionDomain (4/3y)-3+(2/5)=0
y!=0/1
y!=0
y∈R
We add all the numbers together, and all the variables
(+4/3y)-3+(+2/5)=0
We get rid of parentheses
4/3y-3+2/5=0
We calculate fractions
There is no solution for this equation
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