(4/5)(-10y)(5/4)(5x)(0)

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Solution for (4/5)(-10y)(5/4)(5x)(0) equation: 


x in (-oo:+oo)

-10*0*5*(4/5)*(5/4)*x*y = 0

0 = 0

-10*0*5*(4/5)*(5/4)*x = 0

0 = 0

-10*0*5*(4/5)*(5/4) = 0

0 = 0

-10*0*5*(4/5) = 0

0 = 0

-10*0*5 = 0

0 = 0

-10*0 = 0

0 = 0

-10*0 = 0  <=>  -10 = 0 or -10*0 = 0  <=>  0 = 0

-10*0*5 = 0  <=>  -10*0 = 0 or -10*0*5 = 0  <=>  5 = 0

4/5 = 0

4/5 = 0

x belongs to the empty set

-10*0*5*(4/5) = 0  <=>  -10*0*5 = 0 or -10*0*5*(4/5) = 0  <=>  4/5 = 0

5/4 = 0

5/4 = 0

x belongs to the empty set

-10*0*5*(4/5)*(5/4) = 0  <=>  -10*0*5*(4/5) = 0 or -10*0*5*(4/5)*(5/4) = 0  <=>  5/4 = 0

x = 0

-10*0*5*(4/5)*(5/4)*x = 0  <=>  -10*0*5*(4/5)*(5/4) = 0 or -10*0*5*(4/5)*(5/4)*x = 0  <=>  x = 0

y = 0

x naleu017Cy do R

-10*0*5*(4/5)*(5/4)*x*y = 0  <=>  -10*0*5*(4/5)*(5/4)*x = 0 or -10*0*5*(4/5)*(5/4)*x*y = 0  <=>  y = 0

x in (-oo:+oo)

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