(4/5)(y+2)=(1/8)(y+2)

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Solution for (4/5)(y+2)=(1/8)(y+2) equation: 



(4/5)(y+2)=(1/8)(y+2)

We move all terms to the left:

(4/5)(y+2)-((1/8)(y+2))=0



Domain of the equation: 5)(y+2)!=0

y∈R





Domain of the equation: 8)(y+2))!=0

y∈R



We add all the numbers together, and all the variables

(+4/5)(y+2)-((+1/8)(y+2))=0

We multiply parentheses ..

(+4y^2+4/5*2)-((+1/8)(y+2))=0

We calculate fractions


((+4y^2+4*8)(y+2)))/80y^2+()/80y^2=0

We can not solve this equation

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