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(4/5)x+3=x
We move all terms to the left:
(4/5)x+3-(x)=0
Domain of the equation: 5)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+4/5)x-x+3=0
We add all the numbers together, and all the variables
-1x+(+4/5)x+3=0
We multiply parentheses
4x^2-1x+3=0
a = 4; b = -1; c = +3;
Δ = b2-4ac
Δ = -12-4·4·3
Δ = -47
Delta is less than zero, so there is no solution for the equation
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