(4/5)x-1(1/3)=2(1/3)x-3

Solution for (4/5)x-1(1/3)=2(1/3)x-3 equation:

(4/5)x-1(1/3)=2(1/3)x-3

We move all terms to the left:

(4/5)x-1(1/3)-(2(1/3)x-3)=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 3)x-3)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+4/5)x-(2(+1/3)x-3)-1(+1/3)=0

We multiply parentheses

4x^2-(2(+1/3)x-3)-1(+1/3)=0

We calculate fractions


4x^2+()/3x-3)*3))+(-13x)/3x-3)*3))=0

We calculate fractions


4x^2+(()*3x)/9x^2+(-3)*3))+(-13x)*3x)/9x^2=0

We multiply all the terms by the denominator


4x^2*9x^2+(()*3x)+(-3)*3))+(-13x)*3x)=0


We calculate terms in parentheses: +(()*3x), so:

()*3x


Wy multiply elements

36x^4+(()*3x)+(-3)*3))+(-13x)*3x)=0


We calculate terms in parentheses: +(()*3x), so:

()*3x


We do not support expression: x^4