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(4/5q+2=10
We move all terms to the left:
(4/5q+2-(10)=0
Domain of the equation: 5q+2-10!=0We multiply all the terms by the denominator
We move all terms containing q to the left, all other terms to the right
5q!=8
q!=8/5
q!=1+3/5
q∈R
(4=0
We add all the numbers together, and all the variables
=0
q=0/1
q=0
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