(4/5x)+(1/2x)=13

Solution for (4/5x)+(1/2x)=13 equation:

(4/5x)+(1/2x)=13

We move all terms to the left:

(4/5x)+(1/2x)-(13)=0


Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+4/5x)+(+1/2x)-13=0

We get rid of parentheses

4/5x+1/2x-13=0

We calculate fractions


8x/10x^2+5x/10x^2-13=0

We multiply all the terms by the denominator


8x+5x-13*10x^2=0

We add all the numbers together, and all the variables

13x-13*10x^2=0

Wy multiply elements

-130x^2+13x=0

a = -130; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·(-130)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*-130}=\frac{-26}{-260}
=1/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*-130}=\frac{0}{-260}
=0
$