(4/5x)+(1/5x)=87

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Solution for (4/5x)+(1/5x)=87 equation: 



(4/5x)+(1/5x)=87

We move all terms to the left:

(4/5x)+(1/5x)-(87)=0



Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+4/5x)+(+1/5x)-87=0

We get rid of parentheses

4/5x+1/5x-87=0

We multiply all the terms by the denominator


-87*5x+4+1=0

We add all the numbers together, and all the variables

-87*5x+5=0

Wy multiply elements

-435x+5=0

We move all terms containing x to the left, all other terms to the right

-435x=-5

x=-5/-435

x=1/87

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