(4/5x)-(3/2y)=1

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Solution for (4/5x)-(3/2y)=1 equation: 


x in (-oo:+oo)

(4/5)*x-((3/2)*y) = 1 // - 1

(4/5)*x-((3/2)*y)-1 = 0

(4/5)*x+(-3/2)*y-1 = 0

4/5*x-3/2*y-1 = 0 // + -3/2*y-1

4/5*x = -(-3/2*y-1) // : 4/5

x = (-(-3/2*y-1))/4/5

x = 5/4*(1-(-3/2*y))

x = 5/4*(1-(-3/2*y))

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