(4/7)+(7m/2)=(71/14)

Solution for (4/7)+(7m/2)=(71/14) equation:

(4/7)+(7m/2)=(71/14)

We move all terms to the left:

(4/7)+(7m/2)-((71/14))=0

We add all the numbers together, and all the variables

(+7m/2)+(+4/7)-((+71/14))=0

We get rid of parentheses

7m/2+4/7-((+71/14))=0

We calculate fractions


686m^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

686m^2/()+2=0

We multiply all the terms by the denominator


686m^2+2*()=0

We add all the numbers together, and all the variables

686m^2=0

a = 686; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·686·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{1372}=0$