(4/7)+(7m/8)=(95/56)

Solution for (4/7)+(7m/8)=(95/56) equation:

(4/7)+(7m/8)=(95/56)

We move all terms to the left:

(4/7)+(7m/8)-((95/56))=0

We add all the numbers together, and all the variables

(+7m/8)+(+4/7)-((+95/56))=0

We get rid of parentheses

7m/8+4/7-((+95/56))=0

We calculate fractions


13720m^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

13720m^2/()+2=0

We multiply all the terms by the denominator


13720m^2+2*()=0

We add all the numbers together, and all the variables

13720m^2=0

a = 13720; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·13720·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{27440}=0$