(4/7)w-5/3=-5/3

Solution for (4/7)w-5/3=-5/3 equation:

(4/7)w-5/3=-5/3

We move all terms to the left:

(4/7)w-5/3-(-5/3)=0


Domain of the equation: 7)w!=0

w!=0/1

w!=0

w∈R


We add all the numbers together, and all the variables

(+4/7)w-5/3-(-5/3)=0

We multiply parentheses

4w^2-5/3-(-5/3)=0

We get rid of parentheses

4w^2-5/3+5/3=0

We multiply all the terms by the denominator


4w^2*3-5+5=0

We add all the numbers together, and all the variables

4w^2*3=0

Wy multiply elements

12w^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{0}{24}=0$