(4/7)x=6/7

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Solution for (4/7)x=6/7 equation:



(4/7)x=6/7
We move all terms to the left:
(4/7)x-(6/7)=0
Domain of the equation: 7)x!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+4/7)x-(+6/7)=0
We multiply parentheses
4x^2-(+6/7)=0
We get rid of parentheses
4x^2-6/7=0
We multiply all the terms by the denominator
4x^2*7-6=0
Wy multiply elements
28x^2-6=0
a = 28; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·28·(-6)
Δ = 672
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{672}=\sqrt{16*42}=\sqrt{16}*\sqrt{42}=4\sqrt{42}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{42}}{2*28}=\frac{0-4\sqrt{42}}{56} =-\frac{4\sqrt{42}}{56} =-\frac{\sqrt{42}}{14} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{42}}{2*28}=\frac{0+4\sqrt{42}}{56} =\frac{4\sqrt{42}}{56} =\frac{\sqrt{42}}{14} $

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