(4/7x)+(1/4x)=46

Solution for (4/7x)+(1/4x)=46 equation:

(4/7x)+(1/4x)=46

We move all terms to the left:

(4/7x)+(1/4x)-(46)=0


Domain of the equation: 7x)!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+4/7x)+(+1/4x)-46=0

We get rid of parentheses

4/7x+1/4x-46=0

We calculate fractions


16x/28x^2+7x/28x^2-46=0

We multiply all the terms by the denominator


16x+7x-46*28x^2=0

We add all the numbers together, and all the variables

23x-46*28x^2=0

Wy multiply elements

-1288x^2+23x=0

a = -1288; b = 23; c = 0;
Δ = b2-4ac
Δ = 232-4·(-1288)·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-23}{2*-1288}=\frac{-46}{-2576}
=1/56
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+23}{2*-1288}=\frac{0}{-2576}
=0
$