(4/9)t=72

Solution for (4/9)t=72 equation:

(4/9)t=72

We move all terms to the left:

(4/9)t-(72)=0


Domain of the equation: 9)t!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

(+4/9)t-72=0

We multiply parentheses

4t^2-72=0

a = 4; b = 0; c = -72;
Δ = b2-4ac
Δ = 02-4·4·(-72)
Δ = 1152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1152}=\sqrt{576*2}=\sqrt{576}*\sqrt{2}=24\sqrt{2}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{2}}{2*4}=\frac{0-24\sqrt{2}}{8}
=-\frac{24\sqrt{2}}{8}
=-3\sqrt{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{2}}{2*4}=\frac{0+24\sqrt{2}}{8}
=\frac{24\sqrt{2}}{8}
=3\sqrt{2}
$