(4/9)x-12=-1/6(x-12)-3

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Solution for (4/9)x-12=-1/6(x-12)-3 equation: 



(4/9)x-12=-1/6(x-12)-3

We move all terms to the left:

(4/9)x-12-(-1/6(x-12)-3)=0



Domain of the equation: 9)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 6(x-12)-3)!=0

x∈R



We add all the numbers together, and all the variables

(+4/9)x-(-1/6(x-12)-3)-12=0

We multiply parentheses

4x^2-(-1/6(x-12)-3)-12=0

We multiply all the terms by the denominator


4x^2*6(x-12)-12*6(x-12)-1-3)-(-3)=0

We add all the numbers together, and all the variables

4x^2*6(x-12)-12*6(x-12)=0

Wy multiply elements

24x^3(x-72x(x=0

We do not support expression: x^3(x

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