(4/x)+(3/2x)

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Solution for (4/x)+(3/2x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(3/2)*x+4/x = 0

3/2*x^1+4*x^-1 = 0

(3/2*x^2+4*x^0)/(x^1) = 0 // * x^2

x^1*(3/2*x^2+4*x^0) = 0

x^1

(3/2)*x^2+4 = 0

(3/2)*x^2+4 = 0

DELTA = 0^2-(4*4*(3/2))

DELTA = -24

DELTA < 0

x in { } 

x belongs to the empty set

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