(4/x)+(x-3/2x+3)=3

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Solution for (4/x)+(x-3/2x+3)=3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x-((3/2)*x)+4/x+3 = 3 // - 3

x-((3/2)*x)+4/x-3+3 = 0

x+(-3/2)*x+4/x-3+3 = 0

4*x^-1-1/2*x^1 = 0

(4*x^0-1/2*x^2)/(x^1) = 0 // * x^2

x^1*(4*x^0-1/2*x^2) = 0

x^1

(-1/2)*x^2+4 = 0

(-1/2)*x^2+4 = 0

DELTA = 0^2-(4*4*(-1/2))

DELTA = 8

DELTA > 0

x = (8^(1/2)+0)/(2*(-1/2)) or x = (0-8^(1/2))/(2*(-1/2))

x = -2*2^(1/2) or x = 2*2^(1/2)

x in { -2*2^(1/2), 2*2^(1/2)} 

x in { -2*2^(1/2), 2*2^(1/2) }

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