(4/x)-3=(3+x)/4

Solution for (4/x)-3=(3+x)/4 equation:

D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4/x-3 = (x+3)/4 // - (x+3)/4

4/x-((x+3)/4)-3 = 0

(-1*(x+3))/4+4/x-3 = 0

(-1*x*(x+3))/(4*x)+(4^2)/(4*x)+(-3*4*x)/(4*x) = 0

16-1*x*(x+3)-3*4*x = 0

16-x^2-3*x-12*x = 0

16-x^2-15*x = 0

16-x^2-15*x = 0

16-x^2-15*x = 0

DELTA = (-15)^2-(-1*4*16)

DELTA = 289

DELTA > 0

x = (289^(1/2)+15)/(-1*2) or x = (15-289^(1/2))/(-1*2)

x = -16 or x = 1

(x+16)*(x-1) = 0

((x+16)*(x-1))/(4*x) = 0

((x+16)*(x-1))/(4*x) = 0 // * 4*x

(x+16)*(x-1) = 0

( x+16 )

x+16 = 0 // - 16

x = -16

( x-1 )

x-1 = 0 // + 1

x = 1

x in { -16, 1 }