(4/x)=(5/2x)+3

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Solution for (4/x)=(5/2x)+3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4/x = (5/2)*x+3 // - (5/2)*x+3

4/x-((5/2)*x)-3 = 0

(-5/2)*x+4/x-3 = 0

4*x^-1-5/2*x^1-3*x^0 = 0

(4*x^0-5/2*x^2-3*x^1)/(x^1) = 0 // * x^2

x^1*(4*x^0-5/2*x^2-3*x^1) = 0

x^1

(-5/2)*x^2-3*x+4 = 0

(-5/2)*x^2-3*x+4 = 0

DELTA = (-3)^2-(4*4*(-5/2))

DELTA = 49

DELTA > 0

x = (49^(1/2)+3)/(2*(-5/2)) or x = (3-49^(1/2))/(2*(-5/2))

x = -2 or x = 4/5

x in { -2, 4/5} 

x in { -2, 4/5 }

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