(4/x+4)+(3/x-3)=5

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Solution for (4/x+4)+(3/x-3)=5 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4/x+3/x-3+4 = 5 // - 5

4/x+3/x-5-3+4 = 0

7*x^-1 = 4 // : 7

x^-1 = 4/7

-1 < 0

1/(x^1) = 4/7 // * x^1

1 = 4/7*x^1 // : 4/7

7/4 = x^1

x = 7/4

x = 7/4

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