(4/x-1)+(6/3x+1)=(13/3x+1)

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Solution for (4/x-1)+(6/3x+1)=(13/3x+1) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(6/3)*x+4/x-1+1 = (13/3)*x+1 // - (13/3)*x+1

(6/3)*x-((13/3)*x)+4/x-1-1+1 = 0

(6/3)*x+(-13/3)*x+4/x-1-1+1 = 0

4*x^-1-7/3*x^1-1*x^0 = 0

(4*x^0-7/3*x^2-1*x^1)/(x^1) = 0 // * x^2

x^1*(4*x^0-7/3*x^2-1*x^1) = 0

x^1

(-7/3)*x^2-x+4 = 0

(-7/3)*x^2-x+4 = 0

DELTA = (-1)^2-(4*4*(-7/3))

DELTA = 115/3

DELTA > 0

x = ((115/3)^(1/2)+1)/(2*(-7/3)) or x = (1-(115/3)^(1/2))/(2*(-7/3))

x = -3/14*((115/3)^(1/2)+1) or x = -3/14*(1-(115/3)^(1/2))

x in { -3/14*((115/3)^(1/2)+1), -3/14*(1-(115/3)^(1/2))}

x in { -3/14*((115/3)^(1/2)+1), -3/14*(1-(115/3)^(1/2)) }

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