(4/x-3)-(8/2x+5)+(3/x-3)=0

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Solution for (4/x-3)-(8/2x+5)+(3/x-3)=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4/x-((8/2)*x)+3/x-5-3-3 = 0

4/x-4*x+3/x-5-3-3 = 0

7*x^-1-4*x^1-11*x^0 = 0

(7*x^0-4*x^2-11*x^1)/(x^1) = 0 // * x^2

x^1*(7*x^0-4*x^2-11*x^1) = 0

x^1

7-4*x^2-11*x = 0

7-4*x^2-11*x = 0

DELTA = (-11)^2-(-4*4*7)

DELTA = 233

DELTA > 0

x = (233^(1/2)+11)/(-4*2) or x = (11-233^(1/2))/(-4*2)

x = (233^(1/2)+11)/(-8) or x = (11-233^(1/2))/(-8)

x in { (233^(1/2)+11)/(-8), (11-233^(1/2))/(-8)} 

x in { (233^(1/2)+11)/(-8), (11-233^(1/2))/(-8) }

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