(4/x-4)-(3/1-x)=0

Solution for (4/x-4)-(3/1-x)=0 equation:

(4/x-4)-(3/1-x)=0


Domain of the equation: x-4)!=0

x∈R



Domain of the equation: 1-x)!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-1

x!=-1/1

x!=-1

x∈R


We add all the numbers together, and all the variables

(4/x-4)-(-1x)=0

We get rid of parentheses

4/x+1x-4=0

We multiply all the terms by the denominator


1x*x-4*x+4=0

We add all the numbers together, and all the variables

-4x+1x*x+4=0

Wy multiply elements

x^2-4x+4=0

a = 1; b = -4; c = +4;
Δ = b2-4ac
Δ = -42-4·1·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{4}{2}=2$