(4/y)-5=(18/2y)

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Solution for (4/y)-5=(18/2y) equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

4/y-5 = (18/2)*y // - (18/2)*y

4/y-((18/2)*y)-5 = 0

4/y-9*y-5 = 0

4*y^-1-9*y^1-5*y^0 = 0

(4*y^0-9*y^2-5*y^1)/(y^1) = 0 // * y^2

y^1*(4*y^0-9*y^2-5*y^1) = 0

y^1

4-9*y^2-5*y = 0

4-9*y^2-5*y = 0

DELTA = (-5)^2-(-9*4*4)

DELTA = 169

DELTA > 0

y = (169^(1/2)+5)/(-9*2) or y = (5-169^(1/2))/(-9*2)

y = -1 or y = 4/9

y in { -1, 4/9} 

y in { -1, 4/9 }

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