(4/y-1)-(1/2)=(3/y+1)

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Solution for (4/y-1)-(1/2)=(3/y+1) equation: 



(4/y-1)-(1/2)=(3/y+1)

We move all terms to the left:

(4/y-1)-(1/2)-((3/y+1))=0



Domain of the equation: y-1)!=0

y∈R





Domain of the equation: y+1))!=0

y∈R



We add all the numbers together, and all the variables

(4/y-1)-((3/y+1))-(+1/2)=0

We get rid of parentheses

4/y-((3/y+1))-1-1/2=0

We calculate fractions

We do not support eypression: y^3

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