(4/z)+1/z=(2/z)+3

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Solution for (4/z)+1/z=(2/z)+3 equation: 



(4/z)+1/z=(2/z)+3

We move all terms to the left:

(4/z)+1/z-((2/z)+3)=0



Domain of the equation: z)!=0

z!=0/1

z!=0

z∈R





Domain of the equation: z!=0

z∈R





Domain of the equation: z)+3)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

(+4/z)+1/z-((+2/z)+3)=0

We get rid of parentheses

4/z+1/z-((+2/z)+3)=0

We calculate fractions


z/z^2+(-((+2*z)/z^2=0

We add all the numbers together, and all the variables

z/z^2+(-((+2z)/z^2=0

We multiply all the terms by the denominator


z+(-((+2z)=0



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