(4/z-1)-(2/3)=(2/z+1)

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Solution for (4/z-1)-(2/3)=(2/z+1) equation: 



(4/z-1)-(2/3)=(2/z+1)

We move all terms to the left:

(4/z-1)-(2/3)-((2/z+1))=0



Domain of the equation: z-1)!=0

z∈R





Domain of the equation: z+1))!=0

z∈R



We add all the numbers together, and all the variables

(4/z-1)-((2/z+1))-(+2/3)=0

We get rid of parentheses

4/z-((2/z+1))-1-2/3=0

We calculate fractions

We do not support ezpression: z^3

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