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(40+2x)(30+2x)=1496
We move all terms to the left:
(40+2x)(30+2x)-(1496)=0
We add all the numbers together, and all the variables
(2x+40)(2x+30)-1496=0
We multiply parentheses ..
(+4x^2+60x+80x+1200)-1496=0
We get rid of parentheses
4x^2+60x+80x+1200-1496=0
We add all the numbers together, and all the variables
4x^2+140x-296=0
a = 4; b = 140; c = -296;
Δ = b2-4ac
Δ = 1402-4·4·(-296)
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{24336}=156$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(140)-156}{2*4}=\frac{-296}{8} =-37 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(140)+156}{2*4}=\frac{16}{8} =2 $
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