(40+2x)/7=18

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Solution for (40+2x)/7=18 equation:



(40+2x)/7=18
We move all terms to the left:
(40+2x)/7-(18)=0
We add all the numbers together, and all the variables
(2x+40)/7-18=0
We multiply all the terms by the denominator
(2x+40)-18*7=0
We add all the numbers together, and all the variables
(2x+40)-126=0
We get rid of parentheses
2x+40-126=0
We add all the numbers together, and all the variables
2x-86=0
We move all terms containing x to the left, all other terms to the right
2x=86
x=86/2
x=43

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