(40+4x)(50-x)=4000

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Solution for (40+4x)(50-x)=4000 equation: 



(40+4x)(50-x)=4000

We move all terms to the left:

(40+4x)(50-x)-(4000)=0

We add all the numbers together, and all the variables

(4x+40)(-1x+50)-4000=0

We multiply parentheses ..

(-4x^2+200x-40x+2000)-4000=0

We get rid of parentheses

-4x^2+200x-40x+2000-4000=0

We add all the numbers together, and all the variables

-4x^2+160x-2000=0

a = -4; b = 160; c = -2000;
Δ = b2-4ac
Δ = 1602-4·(-4)·(-2000)
Δ = -6400
Delta is less than zero, so there is no solution for the equation

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