(40+x)(0.6)=40(0.5)+0.1x

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Solution for (40+x)(0.6)=40(0.5)+0.1x equation:



(40+x)(0.6)=40(0.5)+0.1x
We move all terms to the left:
(40+x)(0.6)-(40(0.5)+0.1x)=0
We add all the numbers together, and all the variables
(x+40)(0.6)-(40(0.5)+0.1x)=0
We multiply parentheses ..
(+0.6x+24)-(40(0.5)+0.1x)=0
We calculate terms in parentheses: -(40(0.5)+0.1x), so:
40(0.5)+0.1x
determiningTheFunctionDomain 0.1x+40(0.5)
We add all the numbers together, and all the variables
0.1x+20
Back to the equation:
-(0.1x+20)
We add all the numbers together, and all the variables
(0.6x+24)-(0.1x+20)=0
We get rid of parentheses
0.6x-0.1x+24-20=0
We add all the numbers together, and all the variables
0.5x+4=0
We move all terms containing x to the left, all other terms to the right
0.5x=-4
x=-4/0.5
x=-8

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