(40+x)+0.1x=40(0.5)+0.1x

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Solution for (40+x)+0.1x=40(0.5)+0.1x equation:



(40+x)+0.1x=40(0.5)+0.1x
We move all terms to the left:
(40+x)+0.1x-(40(0.5)+0.1x)=0
We add all the numbers together, and all the variables
(x+40)+0.1x-(40(0.5)+0.1x)=0
We add all the numbers together, and all the variables
0.1x+(x+40)-(40(0.5)+0.1x)=0
We get rid of parentheses
0.1x+x-(40(0.5)+0.1x)+40=0
We calculate terms in parentheses: -(40(0.5)+0.1x), so:
40(0.5)+0.1x
determiningTheFunctionDomain 0.1x+40(0.5)
We add all the numbers together, and all the variables
0.1x+20
Back to the equation:
-(0.1x+20)
We add all the numbers together, and all the variables
1.1x-(0.1x+20)+40=0
We get rid of parentheses
1.1x-0.1x-20+40=0
We add all the numbers together, and all the variables
x+20=0
We move all terms containing x to the left, all other terms to the right
x=-20

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