(40-2x)(60-2x)=800

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Solution for (40-2x)(60-2x)=800 equation:



(40-2x)(60-2x)=800
We move all terms to the left:
(40-2x)(60-2x)-(800)=0
We add all the numbers together, and all the variables
(-2x+40)(-2x+60)-800=0
We multiply parentheses ..
(+4x^2-120x-80x+2400)-800=0
We get rid of parentheses
4x^2-120x-80x+2400-800=0
We add all the numbers together, and all the variables
4x^2-200x+1600=0
a = 4; b = -200; c = +1600;
Δ = b2-4ac
Δ = -2002-4·4·1600
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-120}{2*4}=\frac{80}{8} =10 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+120}{2*4}=\frac{320}{8} =40 $

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