(40-3x)/4=(6x+7)/8

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Solution for (40-3x)/4=(6x+7)/8 equation: 



(40-3x)/4=(6x+7)/8

We move all terms to the left:

(40-3x)/4-((6x+7)/8)=0

We add all the numbers together, and all the variables

(-3x+40)/4-((6x+7)/8)=0

We calculate fractions


(-3x)/()+(-((6x+7)*4)/()=0



We calculate terms in parentheses: +(-((6x+7)*4)/(), so:

-((6x+7)*4)/(

We multiply all the terms by the denominator


-((6x+7)*4)



We calculate terms in parentheses: -((6x+7)*4), so:

(6x+7)*4

We multiply parentheses

24x+28

Back to the equation:

-(24x+28)



We get rid of parentheses

-24x-28

Back to the equation:

+(-24x-28)



We get rid of parentheses

(-3x)/()-24x-28=0

We multiply all the terms by the denominator


(-3x)-24x*()-28*()=0

We add all the numbers together, and all the variables

(-3x)-24x*()=0

We get rid of parentheses

-3x-24x*()=0

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