(40-5m)/(20-3x)=5/1

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Solution for (40-5m)/(20-3x)=5/1 equation:


D( x )

20-(3*x) = 0

20-(3*x) = 0

20-(3*x) = 0

20-3*x = 0

20-3*x = 0 // - 20

-3*x = -20 // : -3

x = -20/(-3)

x = 20/3

x in (-oo:20/3) U (20/3:+oo)

(40-(5*m))/(20-(3*x)) = 5/1 // - 5/1

(40-(5*m))/(20-(3*x))-(5/1) = 0

(40-5*m)/(20-3*x)-5 = 0

(40-5*m)/(20-3*x)+(-5*(20-3*x))/(20-3*x) = 0

40-5*(20-3*x)-5*m = 0

15*x-5*m-60 = 0

(15*x-5*m-60)/(20-3*x) = 0

(15*x-5*m-60)/(20-3*x) = 0 // * 20-3*x

15*x-5*m-60 = 0

15*x-5*m-60 = 0 // + -5*m-60

15*x = -(-5*m-60) // : 15

x = (-(-5*m-60))/15

x = (60-(-5*m))/15

x = (60-(-5*m))/15

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