(40-x)/3=4+x

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Solution for (40-x)/3=4+x equation: 


x in (-oo:+oo)

(40-x)/3 = x+4 // - x+4

(40-x)/3-x-4 = 0

(40-x)/3+(3*(-x))/3+(-4*3)/3 = 0

3*(-x)-x-4*3+40 = 0

40-4*x-12 = 0

28-4*x = 0

(28-4*x)/3 = 0

(28-4*x)/3 = 0 // * 3

28-4*x = 0

28-4*x = 0 // - 28

-4*x = -28 // : -4

x = -28/(-4)

x = 7

x = 7

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