(40/100)x=23

Solution for (40/100)x=23 equation:

(40/100)x=23

We move all terms to the left:

(40/100)x-(23)=0


Domain of the equation: 100)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+40/100)x-23=0

We multiply parentheses

40x^2-23=0

a = 40; b = 0; c = -23;
Δ = b2-4ac
Δ = 02-4·40·(-23)
Δ = 3680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3680}=\sqrt{16*230}=\sqrt{16}*\sqrt{230}=4\sqrt{230}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{230}}{2*40}=\frac{0-4\sqrt{230}}{80}
=-\frac{4\sqrt{230}}{80}
=-\frac{\sqrt{230}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{230}}{2*40}=\frac{0+4\sqrt{230}}{80}
=\frac{4\sqrt{230}}{80}
=\frac{\sqrt{230}}{20}
$