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(40/100)x=23
We move all terms to the left:
(40/100)x-(23)=0
Domain of the equation: 100)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+40/100)x-23=0
We multiply parentheses
40x^2-23=0
a = 40; b = 0; c = -23;
Δ = b2-4ac
Δ = 02-4·40·(-23)
Δ = 3680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3680}=\sqrt{16*230}=\sqrt{16}*\sqrt{230}=4\sqrt{230}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{230}}{2*40}=\frac{0-4\sqrt{230}}{80} =-\frac{4\sqrt{230}}{80} =-\frac{\sqrt{230}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{230}}{2*40}=\frac{0+4\sqrt{230}}{80} =\frac{4\sqrt{230}}{80} =\frac{\sqrt{230}}{20} $
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