(40/2x)+(60/2x)=1

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Solution for (40/2x)+(60/2x)=1 equation: 



(40/2x)+(60/2x)=1

We move all terms to the left:

(40/2x)+(60/2x)-(1)=0



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+40/2x)+(+60/2x)-1=0

We get rid of parentheses

40/2x+60/2x-1=0

We multiply all the terms by the denominator


-1*2x+40+60=0

We add all the numbers together, and all the variables

-1*2x+100=0

Wy multiply elements

-2x+100=0

We move all terms containing x to the left, all other terms to the right

-2x=-100

x=-100/-2

x=+50

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