(40k-4*5)/(5+3k)-9=1

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Solution for (40k-4*5)/(5+3k)-9=1 equation: 



(40k-4*5)/(5+3k)-9=1

We move all terms to the left:

(40k-4*5)/(5+3k)-9-(1)=0



Domain of the equation: (5+3k)!=0

We move all terms containing k to the left, all other terms to the right

3k!=-5

k!=-5/3

k!=-1+2/3

k∈R



We add all the numbers together, and all the variables

(40k-20)/(3k+5)-9-1=0

We add all the numbers together, and all the variables

(40k-20)/(3k+5)-10=0

We multiply all the terms by the denominator


(40k-20)-10*(3k+5)=0

We multiply parentheses

(40k-20)-30k-50=0

We get rid of parentheses

40k-30k-20-50=0

We add all the numbers together, and all the variables

10k-70=0

We move all terms containing k to the left, all other terms to the right

10k=70

k=70/10

k=7

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