(40x-20)/20=2x-1

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Solution for (40x-20)/20=2x-1 equation: 


x in (-oo:+oo)

(40*x-20)/20 = 2*x-1 // - 2*x-1

(40*x-20)/20-(2*x)+1 = 0

(40*x-20)/20-2*x+1 = 0

(40*x-20)/20+(-2*20*x)/20+(1*20)/20 = 0

40*x-2*20*x+1*20-20 = 0

20-20 = 0

0 = 0

0/20 = 0

0/20 = 0 // * 20

0 = 0

x belongs to the empty set

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