(41-5x)=(9x-1)

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Solution for (41-5x)=(9x-1) equation: 



(41-5x)=(9x-1)

We move all terms to the left:

(41-5x)-((9x-1))=0

We add all the numbers together, and all the variables

(-5x+41)-((9x-1))=0

We get rid of parentheses

-5x-((9x-1))+41=0



We calculate terms in parentheses: -((9x-1)), so:

(9x-1)

We get rid of parentheses

9x-1

Back to the equation:

-(9x-1)



We get rid of parentheses

-5x-9x+1+41=0

We add all the numbers together, and all the variables

-14x+42=0

We move all terms containing x to the left, all other terms to the right

-14x=-42

x=-42/-14

x=+3

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