(42/5)x=42

Solution for (42/5)x=42 equation:

(42/5)x=42

We move all terms to the left:

(42/5)x-(42)=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+42/5)x-42=0

We multiply parentheses

42x^2-42=0

a = 42; b = 0; c = -42;
Δ = b2-4ac
Δ = 02-4·42·(-42)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*42}=\frac{-84}{84}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*42}=\frac{84}{84}
=1
$