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(42c=35)-(5c-11)=-2
We move all terms to the left:
(42c-(35)-(5c-11))=0
We calculate terms in parentheses: +(42c-35-(5c-11)), so:We get rid of parentheses
42c-35-(5c-11)
determiningTheFunctionDomain 42c-(5c-11)-35
We get rid of parentheses
42c-5c+11-35
We add all the numbers together, and all the variables
37c-24
Back to the equation:
+(37c-24)
37c-24=0
We move all terms containing c to the left, all other terms to the right
37c=24
c=24/37
c=24/37
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