(47+x)=3(x-11)

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Solution for (47+x)=3(x-11) equation: 



(47+x)=3(x-11)

We move all terms to the left:

(47+x)-(3(x-11))=0

We add all the numbers together, and all the variables

(x+47)-(3(x-11))=0

We get rid of parentheses

x-(3(x-11))+47=0



We calculate terms in parentheses: -(3(x-11)), so:

3(x-11)

We multiply parentheses

3x-33

Back to the equation:

-(3x-33)



We get rid of parentheses

x-3x+33+47=0

We add all the numbers together, and all the variables

-2x+80=0

We move all terms containing x to the left, all other terms to the right

-2x=-80

x=-80/-2

x=+40

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